The reaction between NaOH and HCl is a neutralization reaction, where the products are water and a salt (NaCl). The balanced chemical equation for this reaction is:

NaOH + HCl - NaCl + H2O

From the balanced equation, we can see that the stoichiometry of the reaction is 1:1, meaning that one mole of NaOH reacts with one mole of HCl to produce one mole of NaCl and one mole of water.

Given that the volumes of the NaOH and HCl solutions are 60 mL and 50 mL respectively, and both have the same molarity (1.0 M), we can calculate the number of moles of each reactant using the formula:

Moles = Molarity x Volume (in liters)

For NaOH: Moles = 1.0 M x 0.060 L = 0.060 moles
For HCl: Moles = 1.0 M x 0.050 L = 0.050 moles

Since there are more moles of NaOH than HCl, and the reaction consumes NaOH and HCl in a 1:1 ratio, all of the HCl will be consumed before all of the NaOH. Therefore, HCl is the limiting reagent, and there will be excess NaOH.

So, the correct statement is: The limiting reagent is HCl.

Question

The reaction between NaOH and HCl is a neutralization reaction, where the products are water and a salt (NaCl). The balanced chemical equation for this reaction is:

NaOH + HCl -> NaCl + H2O

From the balanced equation, we can see that the stoichiometry of the reaction is 1:1, meaning that one mole of NaOH reacts with one mole of HCl to produce one mole of NaCl and one mole of water.

Given that the volumes of the NaOH and HCl solutions are 60 mL and 50 mL respectively, and both have the same molarity (1.0 M), we can calculate the number of moles of each reactant using the formula:

Moles = Molarity x Volume (in liters)

For NaOH: Moles = 1.0 M x 0.060 L = 0.060 moles
For HCl: Moles = 1.0 M x 0.050 L = 0.050 moles

Since there are more moles of NaOH than HCl, and the reaction consumes NaOH and HCl in a 1:1 ratio, all of the HCl will be consumed before all of the NaOH. Therefore, HCl is the limiting reagent, and there will be excess NaOH.

So, the correct statement is: The limiting reagent is HCl.

Knowee AI · Accepted Answer

The reaction between NaOH and HCl is a neutralization reaction, where the products are water and a salt (NaCl). The balanced chemical equation for this reaction is:

NaOH + HCl -> NaCl + H2O

From the balanced equation, we can see that the stoichiometry of the reaction is 1:1, meaning that one mole of NaOH reacts with one mole of HCl to produce one mole of NaCl and one mole of water.

Given that the volumes of the NaOH and HCl solutions are 60 mL and 50 mL respectively, and both have the same molarity (1.0 M), we can calculate the number of moles of each reactant using the formula:

Moles = Molarity x Volume (in liters)

For NaOH: Moles = 1.0 M x 0.060 L = 0.060 moles
For HCl: Moles = 1.0 M x 0.050 L = 0.050 moles

Since there are more moles of NaOH than HCl, and the reaction consumes NaOH and HCl in a 1:1 ratio, all of the HCl will be consumed before all of the NaOH. Therefore, HCl is the limiting reagent, and there will be excess NaOH.

So, the correct statement is: The limiting reagent is HCl.

In part A of this experiment 60 mL of 1.0 M NaOH is mixed with 50 mL of 1.0 M HCl. Which one of these statements is true?Question 7Select one:The limiting reagent is HCl.This is a stoichiometric mixture, there is no limiting reagent. There is excess HCl. The limiting reagent is NaOH.

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