The circle below is centered at the point (4, -3) and has a radius of length 3. What is its equation?A.(x - 3)2 + (y + 4)2 = 9B.(x - 3)2 + (y - 4)2 = 9C.(x - 4)2 + (y + 3)2 = 32D.(x + 4)2 + (y - 3)2 = 32SUBMITarrow_backPREVIOUS
Question
The circle below is centered at the point (4, -3) and has a radius of length 3. What is its equation?A.(x - 3)2 + (y + 4)2 = 9B.(x - 3)2 + (y - 4)2 = 9C.(x - 4)2 + (y + 3)2 = 32D.(x + 4)2 + (y - 3)2 = 32SUBMITarrow_backPREVIOUS
Solution
The equation of a circle in a coordinate plane is given by (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.
Given that the center of the circle is at the point (4, -3) and the radius is 3, we can substitute these values into the equation to get:
(x - 4)² + (y - (-3))² = 3²
Simplifying this gives:
(x - 4)² + (y + 3)² = 9
So, the correct answer is C. (x - 4)² + (y + 3)² = 9.
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