There are three containers of equal capacity. The ratio of Sulphuric acid to water in the first container is 3 : 2, that in the second container is 7 : 3 and in the third container it is 11 : 4. If all the liquids are mixed together, then the ratio of Sulphuric acid to water in the mixture will be?A] 61 : 29        B] 61 : 28        C] 60 : 29               D] 59 : 29Options :ABCD

To solve this problem, we first need to understand that the ratios given are for equal volumes in each container. This means that we can simply add the parts of Sulphuric acid and water in each container to get the total parts in the mixture.

1. In the first container, the ratio of Sulphuric acid to water is 3:2. This means there are 3 parts Sulphuric acid and 2 parts water.

2. In the second container, the ratio is 7:3. So, there are 7 parts Sulphuric acid and 3 parts water.

3. In the third container, the ratio is 11:4. This means there are 11 parts Sulphuric acid and 4 parts water.

4. To find the total parts of Sulphuric acid in the mixture, we add the parts from each container: 3 (from the first container) + 7 (from the second container) + 11 (from the third container) = 21 parts Sulphuric acid.

5. Similarly, to find the total parts of water in the mixture, we add the parts from each container: 2 (from the first container) + 3 (from the second container) + 4 (from the third container) = 9 parts water.

6. Therefore, the ratio of Sulphuric acid to water in the mixture is 21:9.

However, there seems to be a mistake in the problem or the options provided, as none of the options match the calculated ratio.