In AABC, EF||BC, AB = 4 cm, AE = 1.8 cm, C = A, then the value of EF is​

Given that triangle ABC is an isosceles triangle (since angle C = angle A), and line EF is parallel to BC, we can use the properties of similar triangles to solve for EF.

Step 1: Identify the similar triangles Since EF is parallel to BC, triangle AEF is similar to triangle ABC by the AA (Angle-Angle) criterion of similarity (since corresponding angles are equal when a line is parallel to another).

Step 2: Set up the ratio The sides of similar triangles are in proportion. So, we can write the ratio of corresponding sides as follows:

AE/AB = EF/BC

Step 3: Substitute the given values Substitute the given values into the equation:

1.8/4 = EF/BC

Step 4: Solve for EF We don't know the length of BC, but we know that triangle ABC is isosceles, so BC = AB = 4 cm. Substitute this into the equation:

1.8/4 = EF/4

Cross-multiply to solve for EF:

EF = 1.8 cm

So, the length of EF is 1.8 cm.