An 18.715 g, uncut diamond was dropped inside of a graduated cylinder containing 45.5 mL of water. If the water level rose to 51.0 mL, what is the density of the diamond?
Question
An 18.715 g, uncut diamond was dropped inside of a graduated cylinder containing 45.5 mL of water. If the water level rose to 51.0 mL, what is the density of the diamond?
Solution
To find the density of the diamond, we need to use the formula for density which is mass/volume.
Step 1: Find the volume of the diamond. The volume of the diamond can be found by subtracting the initial volume of the water from the final volume of the water after the diamond was dropped in.
So, Volume of diamond = Final volume - Initial volume = 51.0 mL - 45.5 mL = 5.5 mL
Step 2: Convert the mass of the diamond from grams to milligrams, since the volume is in milliliters and we want the density in g/mL. 1 g = 1 mL (for water), so the mass of the diamond is 18.715 g.
Step 3: Now, we can find the density of the diamond by dividing the mass by the volume. So, Density = Mass/Volume = 18.715 g / 5.5 mL = 3.4027 g/mL
So, the density of the diamond is approximately 3.40 g/mL.
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