Let f(x) be the expression written below. Where will the vertex of the parabola sketched by f(x) be located?(1 Point)𝑓(𝑥)=(𝑥+6)2−43𝑓(𝑥)=(𝑥+6)2−43(−6,43)(−6,43)(6,43)(6,43)(6,−43)(6,−43)(−6,−43)(−6,−43)The graph of f(x) will not have a vertex
Question
Let f(x) be the expression written below. Where will the vertex of the parabola sketched by f(x) be located?(1 Point)𝑓(𝑥)=(𝑥+6)2−43𝑓(𝑥)=(𝑥+6)2−43(−6,43)(−6,43)(6,43)(6,43)(6,−43)(6,−43)(−6,−43)(−6,−43)The graph of f(x) will not have a vertex
Solution
The vertex of the parabola given by the function f(x) = (x+6)² - 43 will be located at (-6, -43).
Here's why:
The general form of a parabola is f(x) = a(x-h)² + k, where (h, k) is the vertex of the parabola.
In the given function f(x) = (x+6)² - 43, you can see that h = -6 and k = -43.
Therefore, the vertex of the parabola is (-6, -43).
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