The cylinder has a height of 10 cm and a radius of 2 cm. The rectangular prism has a height of 9 cm, a width of 3 cm, and a length of 14 cm. Using , what is the surface area of this object to the nearest whole number?a240 cm2 b311 cm2c516 cm2 d541 cm2

To solve this problem, we need to calculate the surface area of both the cylinder and the rectangular prism separately, then add them together.

1. Calculate the surface area of the cylinder: The formula for the surface area of a cylinder is 2πr(h + r), where r is the radius and h is the height. Substituting the given values, we get: 2π * 2 * (10 + 2) = 2π * 2 * 12 = 48π cm².

2. Calculate the surface area of the rectangular prism: The formula for the surface area of a rectangular prism is 2lw + 2lh + 2wh, where l is the length, w is the width, and h is the height. Substituting the given values, we get: 2 * 14 * 3 + 2 * 14 * 9 + 2 * 3 * 9 = 84 + 252 + 54 = 390 cm².

3. Add the surface areas of the cylinder and the rectangular prism: 48π cm² + 390 cm² = 48 * 3.14 cm² + 390 cm² = 150.72 cm² + 390 cm² = 540.72 cm².

Rounding to the nearest whole number, we get 541 cm².

So, the answer is (d) 541 cm².