The water in a tank is drained out at a constant rate. The relationship between the depth of water in the tank, d cm, and time, t in seconds, is given 3d=-6t+210. Determine the initial depth of water in the tank.

A rectangular water tank measures 2.5m long, 2.4m wide and 2.1m high. The tank contained some water up to a height of 1.21m.An inlet pipe was opened and water let to flow into the tank at a rate of 8 litres per minute. After one hour, a drain pipe was opened and water allowed to flow out of the tank at a rate of 6 litres per minute.Calculatei. The height of water in tank after 3 hours.ii. The total time taken to fill up the tank.

Water flows from the bottom of a storage tank at a rate of r(t) = 300 − 6t liters per minute, where 0 ≤ t ≤ 50. Find the amount of water that flows from the tank during the first 30 minutes.

) A tank contains 19 liters of water to start, 4 liters of water flow into the tank while 3 liters of water flow out of the tank per minute. Write a differential for the amount of water A(t) (in liters) in the tank at time t in minutes. =0A(0)= Solve the differential equation: A(t)= Note: use A,A′, etc instead of A(t), dAdt (t) in your answers.

A storage tank is in the form of a cube. When it is full of water, the volume ofwater is 15.625 m 3.If the present depth of water is 1.3 m, find the volume of wateralready used from the tank.

The dimensions of a rectangular water tank are 10 m x 200 m x 6 m. If it is filled with a rectangular pipe of dimension 1 m x 1 m at a speed of 6 km/h, then in how much time will the water rise by 2 m?  Ops:   A. 55 minutes    B. 48 minutes    C. 44 minutes    D. 40 minutes