A buffer solution is most effective when the concentrations of the weak acid and its conjugate base are equal. In this case, the weak acid is acetic acid (CH3COOH).

A. CH3COOK is potassium acetate, the conjugate base of acetic acid. A 1.0 M solution would provide a large excess of base, making the buffer less effective.

B. CH3COONa is sodium acetate, also the conjugate base of acetic acid. A 5.0 M solution would provide an even larger excess of base, making the buffer even less effective.

C. (CH3COO)2Ca is calcium acetate, which can provide two acetate ions per formula unit. A 0.10 M solution would provide an equal concentration of acetate ions as the acetic acid, making this the most effective buffer.

D. CH3COOLi is lithium acetate, the conjugate base of acetic acid. A 0.10 M solution would provide a lower concentration of base, making the buffer less effective.

So, the answer is C. 0.10 M (CH3COO)2Ca.

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A buffer solution is most effective when the concentrations of the weak acid and its conjugate base are equal. In this case, the weak acid is acetic acid (CH3COOH).

A. CH3COOK is potassium acetate, the conjugate base of acetic acid. A 1.0 M solution would provide a large excess of base, making the buffer less effective.

B. CH3COONa is sodium acetate, also the conjugate base of acetic acid. A 5.0 M solution would provide an even larger excess of base, making the buffer even less effective.

C. (CH3COO)2Ca is calcium acetate, which can provide two acetate ions per formula unit. A 0.10 M solution would provide an equal concentration of acetate ions as the acetic acid, making this the most effective buffer.

D. CH3COOLi is lithium acetate, the conjugate base of acetic acid. A 0.10 M solution would provide a lower concentration of base, making the buffer less effective.

So, the answer is C. 0.10 M (CH3COO)2Ca.

Knowee AI · Accepted Answer

A buffer solution is most effective when the concentrations of the weak acid and its conjugate base are equal. In this case, the weak acid is acetic acid (CH3COOH).

A. CH3COOK is potassium acetate, the conjugate base of acetic acid. A 1.0 M solution would provide a large excess of base, making the buffer less effective.

B. CH3COONa is sodium acetate, also the conjugate base of acetic acid. A 5.0 M solution would provide an even larger excess of base, making the buffer even less effective.

C. (CH3COO)2Ca is calcium acetate, which can provide two acetate ions per formula unit. A 0.10 M solution would provide an equal concentration of acetate ions as the acetic acid, making this the most effective buffer.

D. CH3COOLi is lithium acetate, the conjugate base of acetic acid. A 0.10 M solution would provide a lower concentration of base, making the buffer less effective.

So, the answer is C. 0.10 M (CH3COO)2Ca.

Mixing 50 mL of which solution with 50 mL of 0.10 M acetic acid will produce the most effective buffer?A.1.0 M CH3COOKB.5.0 M CH3COONaC.0.10 M (CH3COO)2CaD.0.10 M CH3COOLi

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