Write a C program to check whether an alphabet is vowel or consonant using switch case

Sure! Here is a step-by-step guide to writing a C program to check whether an alphabet is a vowel or consonant using a switch case:

1. Start by including the necessary header file for input/output operations:

   #include <stdio.h>
   

2. Define the main function:

   int main() {
       // code goes here
       return 0;
   }
   

3. Declare a character variable to store the input alphabet:

   char alphabet;
   

4. Prompt the user to enter an alphabet:

   printf("Enter an alphabet: ");
   

5. Read the input alphabet from the user:

   scanf("%c", &alphabet);
   

6. Use a switch case to check whether the input alphabet is a vowel or consonant:

   switch (alphabet) {
       case 'a':
       case 'e':
       case 'i':
       case 'o':
       case 'u':
       case 'A':
       case 'E':
       case 'I':
       case 'O':
       case 'U':
           printf("%c is a vowel.\n", alphabet);
           break;
       default:
           printf("%c is a consonant.\n", alphabet);
           break;
   }
   

7. Finally, end the program:

   return 0;
   

Here's the complete program:

#include <stdio.h>

int main() {
    char alphabet;

    printf("Enter an alphabet: ");
    scanf("%c", &alphabet);

    switch (alphabet) {
        case 'a':
        case 'e':
        case 'i':
        case 'o':
        case 'u':
        case 'A':
        case 'E':
        case 'I':
        case 'O':
        case 'U':
            printf("%c is a vowel.\n", alphabet);
            break;
        default:
            printf("%c is a consonant.\n", alphabet);
            break;
    }

    return 0;
}

This program will prompt the user to enter an alphabet and then determine whether it is a vowel or consonant using a switch case.