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What will be the output of the following code?#include <stdio.h>int main() {    char str[] = "GPT-3";    char *p = str;    printf("%s\n", p + 4);    return 0;}

Question

What will be the output of the following code?#include <stdio.h>int main() {    char str[] = "GPT-3";    char *p = str;    printf("%s\n", p + 4);    return 0;}

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Solution

The output of the code will be "-3".

Here's the step by step explanation:

  1. The code declares a character array str[] and initializes it with the string "GPT-3".

  2. A pointer p is declared and it is pointed to the base address of the string "GPT-3".

  3. printf("%s\n", p + 4); is used to print the string starting from the address p + 4.

  4. In C, string is an array of characters. The base address p points to the first character of the string, which is 'G'.

  5. When we do p + 4, it moves the pointer 4 places to the right. So, it now points to the character '-'.

  6. Hence, when we print the string starting from p + 4, it prints "-3".

  7. The program then returns 0, indicating successful execution.

This problem has been solved

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