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A ray of monochromatic light passes through an equilateral glass prism in such away that the angle of incidence is equal to the angle of emergence and each of theseangles is 3/4 times the angle of the prism. Determine the angle of deviation and therefractive index of the glass prism.

Question

A ray of monochromatic light passes through an equilateral glass prism in such away that the angle of incidence is equal to the angle of emergence and each of theseangles is 3/4 times the angle of the prism. Determine the angle of deviation and therefractive index of the glass prism.

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Solution

Sure, let's solve this step by step.

Step 1: Identify the given values The angle of incidence (i) is equal to the angle of emergence (e) and each of these angles is 3/4 times the angle of the prism (A). So, i = e = 3A/4.

Step 2: Calculate the angle of deviation (D) The formula for the angle of deviation in a prism is D = i + e - A. Substituting the given values, we get D = 3A/4 + 3A/4 - A = A/2.

Step 3: Calculate the refractive index (μ) The formula for the refractive index in a prism is μ = sin((A + D)/2) / sin(A/2). Substituting the values we found, we get μ = sin((A + A/2)/2) / sin(A/2) = sin(3A/4) / sin(A/2).

So, the angle of deviation is A/2 and the refractive index of the glass prism is sin(3A/4) / sin(A/2).

This problem has been solved

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