A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second.y, equals, minus, 16, x, squared, plus, 111, x, plus, 118y=−16x 2 +111x+118

A rocket is launched in the air. Its height in feet is given by h, of, t, equals, minus, 16, t, squared, plus, 8, th(t)=−16t 2 +8t where tt represents the time in seconds after launch. How many seconds have gone by when the rocket is at its highest point?

ProblemEarlier, you were told about a toy rocket fired into the air from the top of a barn. Its height (hℎ) above the ground in yards after x𝑥 seconds is given by the function:h(x)=−5x2+10x+20ℎ(𝑥)=−5𝑥2+10𝑥+20What was the maximum height of the rocket? SolutionThe maximum height was reached by the rocket at one second as you found in part b from the previous example. It takes second to reach the maximum height. We will substitute that value in for x𝑥 in our function and simplify.The maximum height reached by the rocket was yards. What is the time it takes for the rocket to hit the ground? (Use a graph or any other method to solve.)It takes approximately seconds for the rocket to hit the ground. (Round to the nearest tenth.)CheckQuestion 9

Instructions: For the following real-world problem, solve using any method. Use what you’ve learned to determine which method would be best. Put your answer in the context of the problem and determine the appropriate final answer.A rocket carrying fireworks is launched from a hill 400400 feet above a lake. The rocket will fall into the lake after exploding at its maximum height. The model of the trajectory of the rocket and when it hits the lake is given by the equation −10x2+180x+400=0−10𝑥2+180𝑥+400=0 where x𝑥 is the number of seconds that pass.What are the two solutions to this equation? x=𝑥= or In this context, which of these answers makes sense to be the number of seconds that have passed before the rocket hits the lake? x=𝑥=

A model rocket is launched from the deck in Jim’s backyard and the path followed by the rocket can bemodelled by the relation ℎ = −5% ! + 100% + 15, where ℎ, in meters, is the height that the model rocket reachesafter % seconds.a) What is the height of the deck?

A ball is thrown upwards from the ground with a speed of 80 ft/s. If the          height of the ball is given by the function h = 80t − 16t², where t is the time          in seconds. What is the maximum height that the ball will reach?1 pointA. 100 ftB. 120 ftC. 128 ftD. 132 ft