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Juan invested part of ₱15,000 in a fund which earned 8% and invested the          rest in stocks which suffered a 12% loss. At the end of the year his net profit          was ₱200. How much did he invest in stocks?1 pointA. ₱5,000B. ₱7,000C. ₱ 8,000D. ₱10, 000

Question

Juan invested part of ₱15,000 in a fund which earned 8% and invested the          rest in stocks which suffered a 12% loss. At the end of the year his net profit          was ₱200. How much did he invest in stocks?1 pointA. ₱5,000B. ₱7,000C. ₱ 8,000D. ₱10, 000

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Solution

Let's denote the amount Juan invested in the fund as F and the amount he invested in stocks as S. We know that the total amount he invested is ₱15,000, so we can write the equation:

F + S = ₱15,000

We also know that the fund earned 8% and the stocks suffered a 12% loss. At the end of the year, his net profit was ₱200. This gives us another equation:

0.08F - 0.12S = ₱200

We now have a system of two equations, and we can solve it step by step.

First, let's express F from the first equation:

F = ₱15,000 - S

Now we can substitute F in the second equation:

0.08(₱15,000 - S) - 0.12S = ₱200 ₱1,200 - 0.08S - 0.12S = ₱200 ₱1,000 = 0.2S

From this, we find that S = ₱5,000. So, Juan invested ₱5,000 in stocks. The answer is A. ₱5,000.

This problem has been solved

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