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A football team played 38 games.19 games were played at home and the rest were played away.The team won a total of 21 games.They drew 4 games away.2 of the 10 games they lost were at home.Copy and complete the two way table.

Question

A football team played 38 games.19 games were played at home and the rest were played away.The team won a total of 21 games.They drew 4 games away.2 of the 10 games they lost were at home.Copy and complete the two way table.

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Solution

Sure, here is the completed two-way table:

Home Away Total
Won 9 12 21
Draw 0 4 4
Lost 2 8 10
Total 19 19 38

Here's how we got these numbers:

  1. The team played 38 games in total, with 19 games at home and the rest, which is 19 games, away.
  2. They won a total of 21 games. The question doesn't specify where these games were won, so we can't fill in the 'Won' row yet.
  3. They drew 4 games away. So, we can fill in the 'Draw' row with 0 games at home (since it doesn't mention any home draws) and 4 games away.
  4. They lost 10 games in total, with 2 of these at home. So, we can fill in the 'Lost' row with 2 games at home and 8 games away (since 10 total lost - 2 at home = 8 away).
  5. Now, we can fill in the 'Won' row. We know that they won 21 games in total, drew 0 at home and lost 2 at home. So, they must have won 19 - 0 - 2 = 17 games at home. Similarly, they won 21 - 17 = 4 games away.
  6. But, we have a contradiction here. They can't have won 4 games away because we know from the 'Draw' and 'Lost' rows that they won 12 games away (19 total away - 4 draw away - 3 lost away = 12 won away). So, there must be a mistake in the 'Won' row at home. They must have won 21 - 12 = 9 games at home, not 17.
  7. So, the final table is as above.

This problem has been solved

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