A football team played 38 games.19 games were played at home and the rest were played away.The team won a total of 21 games.They drew 4 games away.2 of the 10 games they lost were at home.Copy and complete the two way table.
Question
A football team played 38 games.19 games were played at home and the rest were played away.The team won a total of 21 games.They drew 4 games away.2 of the 10 games they lost were at home.Copy and complete the two way table.
Solution
Sure, here is the completed two-way table:
| Home | Away | Total | |
|---|---|---|---|
| Won | 9 | 12 | 21 |
| Draw | 0 | 4 | 4 |
| Lost | 2 | 8 | 10 |
| Total | 19 | 19 | 38 |
Here's how we got these numbers:
- The team played 38 games in total, with 19 games at home and the rest, which is 19 games, away.
- They won a total of 21 games. The question doesn't specify where these games were won, so we can't fill in the 'Won' row yet.
- They drew 4 games away. So, we can fill in the 'Draw' row with 0 games at home (since it doesn't mention any home draws) and 4 games away.
- They lost 10 games in total, with 2 of these at home. So, we can fill in the 'Lost' row with 2 games at home and 8 games away (since 10 total lost - 2 at home = 8 away).
- Now, we can fill in the 'Won' row. We know that they won 21 games in total, drew 0 at home and lost 2 at home. So, they must have won 19 - 0 - 2 = 17 games at home. Similarly, they won 21 - 17 = 4 games away.
- But, we have a contradiction here. They can't have won 4 games away because we know from the 'Draw' and 'Lost' rows that they won 12 games away (19 total away - 4 draw away - 3 lost away = 12 won away). So, there must be a mistake in the 'Won' row at home. They must have won 21 - 12 = 9 games at home, not 17.
- So, the final table is as above.
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