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What will be the output of the following code?This question is required.*class Base {public void display() {System.out.println("Base");}}class Derived extends Base {public void display() {System.out.println("Derived");}}public class Main {public static void main(String[] args) {Base b = new Derived();b.display();}}

Question

What will be the output of the following code?This question is required.*class Base {public void display() {System.out.println("Base");}}class Derived extends Base {public void display() {System.out.println("Derived");}}public class Main {public static void main(String[] args) {Base b = new Derived();b.display();}}

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Solution

The output of the code will be "Derived".

Here's the step by step explanation:

  1. The Base class has a method called display() that prints out "Base".

  2. The Derived class extends Base and overrides the display() method to print out "Derived" instead.

  3. In the main method, a new Derived object is created but it's referred to with a Base reference.

  4. When b.display() is called, because of polymorphism, the Java Virtual Machine (JVM) calls the display() method of the actual object that b refers to, which is the Derived class. Therefore, "Derived" is printed out.

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