If a pool cue of mass 0.50 kg hits another ball for 54 milli seconds with a force of 2 N, what is the impulse of this force?*1 point0.108 kgm/s1.080 kgm/s10.80 kgm/s108.0 kgm/s
Question
If a pool cue of mass 0.50 kg hits another ball for 54 milli seconds with a force of 2 N, what is the impulse of this force?*1 point0.108 kgm/s1.080 kgm/s10.80 kgm/s108.0 kgm/s
Solution
Impulse is calculated by multiplying the force by the time it is applied. In this case, the force is 2 N and the time is 54 milliseconds, which is 0.054 seconds (since 1 second is 1000 milliseconds).
So, the impulse (J) can be calculated as follows:
J = F * t J = 2 N * 0.054 s J = 0.108 kgm/s
So, the impulse of the force is 0.108 kgm/s.
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