The cell will act as a Galvanic Cell.

Here's why:

In a galvanic cell, the redox reaction is spontaneous and produces an electric current. In this case, the metal M1 is being oxidized and metal M2 is being reduced.

The standard cell potential (E°cell) can be calculated using the formula:

E°cell = E°cathode - E°anode

Given that the standard reduction potential of the cathode (E°cathode) is 0.5 V and the standard oxidation potential of the anode (E°anode) is 1.0 V, we can substitute these values into the formula:

E°cell = 0.5 V - (-1.0 V) = 1.5 V

Since the standard cell potential is positive, the cell reaction is spontaneous, indicating that the cell is a galvanic cell.

Question

The cell will act as a Galvanic Cell.

Here's why:

In a galvanic cell, the redox reaction is spontaneous and produces an electric current. In this case, the metal M1 is being oxidized and metal M2 is being reduced.

The standard cell potential (E°cell) can be calculated using the formula:

E°cell = E°cathode - E°anode

Given that the standard reduction potential of the cathode (E°cathode) is 0.5 V and the standard oxidation potential of the anode (E°anode) is 1.0 V, we can substitute these values into the formula:

E°cell = 0.5 V - (-1.0 V) = 1.5 V

Since the standard cell potential is positive, the cell reaction is spontaneous, indicating that the cell is a galvanic cell.

Knowee AI · Accepted Answer

The cell will act as a Galvanic Cell.

Here's why:

In a galvanic cell, the redox reaction is spontaneous and produces an electric current. In this case, the metal M1 is being oxidized and metal M2 is being reduced.

The standard cell potential (E°cell) can be calculated using the formula:

E°cell = E°cathode - E°anode

Given that the standard reduction potential of the cathode (E°cathode) is 0.5 V and the standard oxidation potential of the anode (E°anode) is 1.0 V, we can substitute these values into the formula:

E°cell = 0.5 V - (-1.0 V) = 1.5 V

Since the standard cell potential is positive, the cell reaction is spontaneous, indicating that the cell is a galvanic cell.

If two metals, M1 (left side) and M2 (Right Side) dipped in their own electrolytes of 1 M and separated by a salt bridge, the std. reduction potential of cathode is 0.5 V and std. oxidation potential of 1.0 V. The cell will act as 1 pointElectrolytic cellGalvanic CellFuel cellSolid oxide fuel cell

Question

Solution

Similar Questions

Upgrade your grade with Knowee