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A sum of money placed at compound interest 12 times itself in 5 years. How many times it becomes in 10 years?Choose the best optionClear Response134124154144

Question

A sum of money placed at compound interest 12 times itself in 5 years. How many times it becomes in 10 years?Choose the best optionClear Response134124154144

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Solution

The problem is about compound interest.

Given that the sum of money becomes 12 times itself in 5 years, this means that the compound interest rate is such that the initial sum (P) becomes 12P after 5 years.

If we let r be the interest rate, then the formula for compound interest is:

P(1 + r)^n = A

where: P is the initial sum, r is the interest rate, n is the number of compounding periods, A is the amount after n periods.

In this case, we know that P(1 + r)^5 = 12P.

If we want to find out how many times the sum becomes in 10 years, we need to solve for A in the equation P(1 + r)^10 = A.

Since we know that (1 + r)^5 = 12, we can square both sides of this equation to find (1 + r)^10.

(1 + r)^10 = 12^2 = 144

Therefore, the sum becomes 144 times itself in 10 years.

So, the correct option is 144.

This problem has been solved

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