What Is The Output Of The Following Code?#IncludeVoid Main(){    Int S=0;    While(S++<10)    {        If(S<4 && S<9)            Continue;        Printf("\N%D\T",S);    }}

The output of the given code will be:

4 5 6 7 8 9 10 11

Here's the step-by-step explanation:

1. The variable S is initialized with the value 0.
2. The while loop will run as long as S is less than 10. However, due to the S++ in the condition, S will be incremented by 1 in each iteration.
3. Inside the loop, there's an if condition that checks if S is less than 4 and less than 9. If both conditions are true, the continue statement will skip the rest of the current loop iteration and proceed to the next iteration. This means that the printf statement will not be executed when S is less than 4.
4. The printf statement will print the value of S followed by a tab character. This will happen for the values of S from 4 to 10.
5. After the 10th iteration, S will be incremented to 11 due to the S++ in the while condition, but the loop will not run for S=11 because it's not less than 10. However, the printf statement will still be executed for S=11 because it's outside the while loop. So, the final output will include 11.