Knowee
Questions
Features
Study Tools

The probability is 0.182 that a person with HIVpositive at the age of 20 years will live till 63 years of age. Among6 HIV positive patients of 20 years, what is the mean of the binomail distribution that thenumber of patients alive till 63 years ?YOU CAN USE ONLINE SIMULATION CALCULATOR.

Question

The probability is 0.182 that a person with HIVpositive at the age of 20 years will live till 63 years of age. Among6 HIV positive patients of 20 years, what is the mean of the binomail distribution that thenumber of patients alive till 63 years ?YOU CAN USE ONLINE SIMULATION CALCULATOR.

🧐 Not the exact question you are looking for?Go ask a question

Solution

The mean of a binomial distribution is calculated by multiplying the number of trials (n) by the probability of success (p). In this case, the number of trials is the number of patients, which is 6, and the probability of success is the probability that a patient will live till 63 years of age, which is 0.182.

So, the mean (μ) of the binomial distribution is:

μ = n * p μ = 6 * 0.182 μ = 1.092

So, on average, we would expect about 1 (or to be more precise, 1.092) out of 6 HIV positive patients of 20 years to live till 63 years of age.

This problem has been solved

Similar Questions

In the caseThe probability is 0.182 that a person with HIVpositive at the age of 20 years will live till 63 years of age. Among6 HIV positive patients of 20 years, what is the Standard deviation of the Binomial distribution that thenumber of patients alive till 63 years ?YOU CAN USE ONLINE SIMULATION CALCULATOR.

The probability is 0.182 that a person with HIVpositive at the age of 20 years will live till 63 years of age. Among6 HIV positive patients of 20 years, what is the probability that thenumber of patients alive till 63 years isa. from the distribution table find the nature of curve whether it is ____________YOU CAN USE ONLINE SIMULATION CALCULATOR.

Suppose a manufacturer wants to estimate the averagelifespan of a new product they have developed. Theyrandomly select 15 products and test them until they fail.It is known that the average lifespan is 120 hours, with astandard deviation of 10 hours. Assume that the lifespanof the products follows a normal distribution. Themanufacturer wants to know the probability that theaverage lifespan of the product is greater than 130 hours.

Insurance: An insurance company sells a 1-year term life insurance policy to an 83-year-old man. The man pays a premium of $4700. If he dies within 1 year, the company will pay $82,000 to his beneficiary. According to the U.S. Centers for Disease Control and Prevention, the probability that an 83-year-old man will be alive 1 year later is 0.9437. Let X be the profit made by the insurance company.Part: 0 / 20 of 2 Parts CompletePart 1 of 2(a) Find the probability distribution.The probability distribution isx 82000 4700Px

If the mean age of infection with a pathogen is 8 years in a population with mean life expectancy of 80 years, what is the approximate R0 for the pathogen?1 point

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.