To solve this problem, we need to use the formula for the intensity of light, which is given by:

I = P / (4πd²)

where:
- I is the intensity of the light,
- P is the power of the light source, and
- d is the distance from the light source.

We know that the minimum intensity of light that can be detected by the unaided human eye is approximately 10^-10 W/m². We also know that the power of the Sun is about 3.8 x 10^26 W.

We can rearrange the formula to solve for d:

d = sqrt(P / (4πI))

Substituting the known values:

d = sqrt((3.8 x 10^26 W) / (4π x 10^-10 W/m²))

Solving this equation gives:

d ≈ 7.3 x 10^16 m

So, the Sun could just be seen by the unaided eye at a distance of approximately 7.3 x 10^16 meters.

Question

To solve this problem, we need to use the formula for the intensity of light, which is given by:

I = P / (4πd²)

where:
- I is the intensity of the light,
- P is the power of the light source, and
- d is the distance from the light source.

We know that the minimum intensity of light that can be detected by the unaided human eye is approximately 10^-10 W/m². We also know that the power of the Sun is about 3.8 x 10^26 W.

We can rearrange the formula to solve for d:

d = sqrt(P / (4πI))

Substituting the known values:

d = sqrt((3.8 x 10^26 W) / (4π x 10^-10 W/m²))

Solving this equation gives:

d ≈ 7.3 x 10^16 m

So, the Sun could just be seen by the unaided eye at a distance of approximately 7.3 x 10^16 meters.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for the intensity of light, which is given by:

I = P / (4πd²)

where:
- I is the intensity of the light,
- P is the power of the light source, and
- d is the distance from the light source.

We know that the minimum intensity of light that can be detected by the unaided human eye is approximately 10^-10 W/m². We also know that the power of the Sun is about 3.8 x 10^26 W.

We can rearrange the formula to solve for d:

d = sqrt(P / (4πI))

Substituting the known values:

d = sqrt((3.8 x 10^26 W) / (4π x 10^-10 W/m²))

Solving this equation gives:

d ≈ 7.3 x 10^16 m

So, the Sun could just be seen by the unaided eye at a distance of approximately 7.3 x 10^16 meters.

The minimum intensity of light that can be detected by unaided human eye is approximately 10 10Wm 2 Estimate the distance at which the Sun could just be seen by unaided eye

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