In THREE points, relate the equation of continuity with the propulsion of a rocket.
Question
In THREE points, relate the equation of continuity with the propulsion of a rocket.
Solution
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The equation of continuity in fluid dynamics states that the mass flow rate in a fluid system remains constant. This principle is applied in rocket propulsion where the mass of the rocket fuel being expelled out of the rocket (product of the fuel's density, velocity, and cross-sectional area of the exhaust) remains constant.
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As the rocket fuel is burned and expelled, the mass of the rocket decreases. However, according to the equation of continuity, the velocity of the expelled gases must increase to maintain a constant mass flow rate. This increased velocity of the expelled gases results in an increased thrust force propelling the rocket upwards.
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The equation of continuity also explains why rockets are more efficient in space. In space, there is no external pressure acting on the exhaust gases. This allows the gases to expand more and thus be expelled at higher velocities, resulting in greater thrust. This wouldn't be possible on Earth due to atmospheric pressure.
Similar Questions
Consider a rocket which has a mass of 2.10 x 106 kg at takeoff, and its engines produce a constant thrust of 3.1 x 107 N as it takes off vertically. Choose the best response for the three quantities below:a) the initial acceleration of the rocket;b) the time needed for the rocket to reach a speed of 50 m/s, assuming constant mass and thrust; andc) description of the actual acceleration and time needed to reach 50 m/s factoring in that as the rocket ascends, fuel is expelled and thus the mass decreases significantly.Group of answer choicesa) 𝑎𝑜=4.96𝑚/𝑠2b) 𝑡=10.1𝑠c) Assuming the rocket can produce a constant thrust force, F0, the gravitational force acting downward on the rocket will not change, so the net force acting on the rocket will be constant. So, the acceleration will remain constant as the rocket burns fuel and the time it would take to reach 50 m/s will still be about 10.1 seconds.a) 𝑎𝑜=4.96𝑚/𝑠2b) 𝑡=10.1𝑠c) Assuming the rocket can produce a constant thrust force, F0, the gravitational force acting downward on the rocket will become lessened due to the loss of mass and so the net force acting upward will become larger. So, the acceleration will will increase as the rocket burns fuel and the time it would take to reach 50 m/s will be less than 10.1 secondsa) 𝑎𝑜=14.8𝑚/𝑠2b) 𝑡=3.38𝑠c) Assuming the rocket can produce a constant thrust force, F0, the gravitational force acting downward on the rocket will not change, so the net force acting on the rocket will be constant. So, the acceleration will remain constant as the rocket burns fuel and the time it would take to reach 50 m/s will still be about 3.38 secondsa) 𝑎𝑜=14.8𝑚/𝑠2b) 𝑡=3.38𝑠c) Assuming the rocket can produce a constant thrust force, F0, the gravitational force acting downward on the rocket will become lessened due to the loss of mass and so the net force acting upward will become larger. So, the acceleration will will increase as the rocket burns fuel and the time it would take to reach 50 m/s will be less than 3.38 seconds
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