The compound that forms both hydrogen and oxygen at the electrodes when a concentrated aqueous solution is electrolyzed is H2SO4 (Sulfuric Acid).

Here's the step by step process:

1. When sulfuric acid is electrolyzed, it ionizes into two hydrogen ions (H+) and one sulfate ion (SO4^2-).

2. At the cathode (negative electrode), hydrogen ions gain electrons (reduction process) to form hydrogen gas. The half-reaction is: 2H+ + 2e- - H2

3. At the anode (positive electrode), water molecules lose electrons (oxidation process) to form oxygen gas and hydrogen ions. The half-reaction is: 2H2O - O2 + 4H+ + 4e-

4. Therefore, both hydrogen and oxygen gases are formed at the electrodes during the electrolysis of sulfuric acid.

So, the correct answer is C. H2SO4.

Question

The compound that forms both hydrogen and oxygen at the electrodes when a concentrated aqueous solution is electrolyzed is H2SO4 (Sulfuric Acid).

Here's the step by step process:

1. When sulfuric acid is electrolyzed, it ionizes into two hydrogen ions (H+) and one sulfate ion (SO4^2-).

2. At the cathode (negative electrode), hydrogen ions gain electrons (reduction process) to form hydrogen gas. The half-reaction is: 2H+ + 2e- -> H2

3. At the anode (positive electrode), water molecules lose electrons (oxidation process) to form oxygen gas and hydrogen ions. The half-reaction is: 2H2O -> O2 + 4H+ + 4e-

4. Therefore, both hydrogen and oxygen gases are formed at the electrodes during the electrolysis of sulfuric acid.

So, the correct answer is C. H2SO4.

Knowee AI · Accepted Answer

The compound that forms both hydrogen and oxygen at the electrodes when a concentrated aqueous solution is electrolyzed is H2SO4 (Sulfuric Acid).

Here's the step by step process:

1. When sulfuric acid is electrolyzed, it ionizes into two hydrogen ions (H+) and one sulfate ion (SO4^2-).

2. At the cathode (negative electrode), hydrogen ions gain electrons (reduction process) to form hydrogen gas. The half-reaction is: 2H+ + 2e- -> H2

3. At the anode (positive electrode), water molecules lose electrons (oxidation process) to form oxygen gas and hydrogen ions. The half-reaction is: 2H2O -> O2 + 4H+ + 4e-

4. Therefore, both hydrogen and oxygen gases are formed at the electrodes during the electrolysis of sulfuric acid.

So, the correct answer is C. H2SO4.

Which compound forms both hydrogen and oxygen at the electrodes when a concentratedaqueous solution is electrolyzed?A. KIB. NaClC. H 2 SO4D. AgNO

Question

Solution

Similar Questions

Upgrade your grade with Knowee