The length of Maya's rectangular living room is 9 meters and the distance between opposite corners is 10 meters. What is the width of Maya's living room? If necessary, round to the nearest tenth.
Question
The length of Maya's rectangular living room is 9 meters and the distance between opposite corners is 10 meters. What is the width of Maya's living room? If necessary, round to the nearest tenth.
Solution
To solve this problem, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In this case, the length of the living room is one side of the triangle, the width of the living room is the second side, and the distance between opposite corners is the hypotenuse.
We know that the length is 9 meters and the hypotenuse is 10 meters.
So, we can set up the equation as follows:
(Length)^2 + (Width)^2 = (Hypotenuse)^2
Substituting the given values:
(9)^2 + (Width)^2 = (10)^2
81 + (Width)^2 = 100
To solve for Width, we subtract 81 from both sides:
(Width)^2 = 100 - 81
(Width)^2 = 19
Finally, we take the square root of both sides to solve for Width:
Width = √19 ≈ 4.4 meters
So, the width of Maya's living room is approximately 4.4 meters.
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