Assume x is declared as an int, but we do not know its value.What is the value of x == !(!x)?It's always 1It's 1 if x is 0 or 1, otherwise its 0It's always 0It's undefinedSubmit
Question
Assume x is declared as an int, but we do not know its value.What is the value of x == !(!x)?It's always 1It's 1 if x is 0 or 1, otherwise its 0It's always 0It's undefinedSubmit
Solution
The value of x == !(!x) is always 1. This is because the double negation (!!) will always return the boolean value of the original variable. In C++, any non-zero value is considered as true (1) and zero is considered as false (0). So, when we negate it twice, we get the boolean value of the original integer. Therefore, regardless of the value of x, x is always equal to !(!x).
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