The first member of alkyne homologous series is(a) ethyne(b) ethene(c) propyne(d) methane
Question
The first member of alkyne homologous series is(a) ethyne(b) ethene(c) propyne(d) methane
Solution
The first member of the alkyne homologous series is ethyne.
Here's why:
Alkynes are hydrocarbons that contain a triple bond between two carbon atoms. The general formula for alkynes is CnH2n-2.
The smallest possible alkyne must contain two carbon atoms (since a triple bond requires two carbon atoms).
So, if we plug n=2 into the formula, we get C2H2, which is the molecular formula for ethyne.
Therefore, the first member of the alkyne homologous series is ethyne (option a).
Similar Questions
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