det(A)=1×(93−(−7)(−6))−(−3)×(−33−(−7)(2))+2×(−36−92)−5×(−3×(−6)−9×2)+0
Question
det(A)=1×(93−(−7)(−6))−(−3)×(−33−(−7)(2))+2×(−36−92)−5×(−3×(−6)−9×2)+0
Solution
The given expression is a determinant of a matrix. Let's solve it step by step:
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Simplify the expressions in the parentheses:
det(A) = 1×(93 - (−7)(−6)) - (−3)×(−33 - (−7)(2)) + 2×(−36 - 92) - 5×(−3×(−6) - 9×2) + 0 = 1×(93 - 42) - (−3)×(−33 - 14) + 2×(−128) - 5×(18 - 18) + 0
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Perform the multiplications and subtractions:
det(A) = 1×51 - (−3)×(−47) + 2×(−128) - 5×0 + 0 = 51 - 141 + (−256) - 0 + 0
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Add and subtract the results:
det(A) = 51 - 141 - 256 = -90 - 256 = -346
So, the determinant of the matrix A is -346.
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