The product of any three consecutive natural numbers is always divisible by 6.

Here's why:

Let's take any three consecutive natural numbers. We can represent them as n, n+1, and n+2.

1. At least one of these numbers is even, which means it's divisible by 2.

2. Also, in any set of three consecutive numbers, at least one of them is a multiple of 3.

Therefore, the product of any three consecutive natural numbers is always divisible by 2 and 3, which means it's divisible by 6.

So, the correct option is 6.

Question

The product of any three consecutive natural numbers is always divisible by 6.

Here's why:

Let's take any three consecutive natural numbers. We can represent them as n, n+1, and n+2.

1. At least one of these numbers is even, which means it's divisible by 2.

2. Also, in any set of three consecutive numbers, at least one of them is a multiple of 3.

Therefore, the product of any three consecutive natural numbers is always divisible by 2 and 3, which means it's divisible by 6.

So, the correct option is 6.

Knowee AI · Accepted Answer

The product of any three consecutive natural numbers is always divisible by 6.

Here's why:

Let's take any three consecutive natural numbers. We can represent them as n, n+1, and n+2.

1. At least one of these numbers is even, which means it's divisible by 2.

2. Also, in any set of three consecutive numbers, at least one of them is a multiple of 3.

Therefore, the product of any three consecutive natural numbers is always divisible by 2 and 3, which means it's divisible by 6.

So, the correct option is 6.

The product of any three consecutive natural numbers is always divisible byOptions36915