The names of 5 students from section A, 6 from section B and 7 students from section C were selected. The age of all the 18 students was different. Again, one name was selected from them and it was found that it was of section B. What was the probability that it was the youngest student of the section B?

To solve this problem, we need to understand that the event of selecting a student from section B and the event of selecting the youngest student from section B are independent.

Step 1: Calculate the total number of students. We have 5 students from section A, 6 from section B, and 7 from section C. So, the total number of students is 5 + 6 + 7 = 18 students.

Step 2: Calculate the probability of selecting a student from section B. The probability of selecting a student from section B is the number of students in section B divided by the total number of students. So, the probability is 6/18 = 1/3.

Step 3: Calculate the probability of selecting the youngest student from section B. Since all students have different ages, there is only one youngest student in section B. So, the probability of selecting the youngest student from section B is 1/6.

Step 4: Calculate the probability of both events happening. Since these are independent events, the probability of both events happening is the product of their individual probabilities. So, the probability is (1/3) * (1/6) = 1/18.

So, the probability that the selected student is the youngest student from section B is 1/18.

To solve this problem, we need to understand that the events are independent. The event of choosing a student from section B and the event of choosing the youngest student from section B are not related.

Step 1: Calculate the total number of students. We have 5 students from section A, 6 from section B, and 7 from section C. So, the total number of students is 5 + 6 + 7 = 18 students.

Step 2: Calculate the probability of choosing a student from section B. The probability of choosing a student from section B is the number of students in section B divided by the total number of students. So, the probability is 6/18 = 1/3.

Step 3: Calculate the probability of choosing the youngest student from section B. Since all students have different ages, there is only one youngest student in section B. So, the probability of choosing the youngest student from section B is 1/6.

Step 4: Calculate the final probability. The final probability is the product of the probability of choosing a student from section B and the probability of choosing the youngest student from section B. So, the final probability is 1/3 * 1/6 = 1/18.

So, the probability that the selected student was the youngest student from section B is 1/18.