This problem can be solved using Python. Here is a step-by-step guide on how to implement a hash table with linear probing:

1. First, define a class for the hash table. This class will have methods for inserting keys, resolving collisions using linear probing, and displaying the keys and their corresponding indices.

```python
class HashTable:
def __init__(self, size):
self.size = size
self.table = [None]*size
self.keys = []

def insert(self, key):
index = key % self.size
if self.table[index] is None:
self.table[index] = key
self.keys.append((index, key))
else:
self.linear_probing(index, key)

def linear_probing(self, index, key):
for i in range(index+1, self.size):
if self.table[i] is None:
self.table[i] = key
self.keys.append((i, key))
return
for i in range(0, index):
if self.table[i] is None:
self.table[i] = key
self.keys.append((i, key))
return

def display(self):
self.keys.sort()
for key in self.keys:
print(f"index: {key[0]}, value: {key[1]}")
```

2. Next, get the size of the hash table and the keys to be inserted from the user.

```python
size = int(input())
n = int(input())
keys = list(map(int, input().split()))
```

3. Create an instance of the HashTable class and insert the keys into the hash table.

```python
hash_table = HashTable(size)
for key in keys:
hash_table.insert(key)
```

4. Finally, display the keys and their corresponding indices.

```python
hash_table.display()
```

This program will take a series of integers as input, hash them into a hash table, resolve any collisions using linear probing, and then display the keys and their corresponding indices in ascending order of their original insertion.

Question

This problem can be solved using Python. Here is a step-by-step guide on how to implement a hash table with linear probing:

1. First, define a class for the hash table. This class will have methods for inserting keys, resolving collisions using linear probing, and displaying the keys and their corresponding indices.

```python
class HashTable:
    def __init__(self, size):
        self.size = size
        self.table = [None]*size
        self.keys = []

def insert(self, key):
        index = key % self.size
        if self.table[index] is None:
            self.table[index] = key
            self.keys.append((index, key))
        else:
            self.linear_probing(index, key)

def linear_probing(self, index, key):
        for i in range(index+1, self.size):
            if self.table[i] is None:
                self.table[i] = key
                self.keys.append((i, key))
                return
        for i in range(0, index):
            if self.table[i] is None:
                self.table[i] = key
                self.keys.append((i, key))
                return

def display(self):
        self.keys.sort()
        for key in self.keys:
            print(f"index: {key[0]}, value: {key[1]}")
```

2. Next, get the size of the hash table and the keys to be inserted from the user.

```python
size = int(input())
n = int(input())
keys = list(map(int, input().split()))
```

3. Create an instance of the HashTable class and insert the keys into the hash table.

```python
hash_table = HashTable(size)
for key in keys:
    hash_table.insert(key)
```

4. Finally, display the keys and their corresponding indices.

```python
hash_table.display()
```

This program will take a series of integers as input, hash them into a hash table, resolve any collisions using linear probing, and then display the keys and their corresponding indices in ascending order of their original insertion.

Knowee AI · Accepted Answer