The maximum possible bandwidth (B) of a fiber optic cable can be estimated using the following formula:

B = 0.2 / (tp * L)

where:
- tp is the total pulse broadening, and
- L is the distance.

In this case, tp = 0.15 μs and L = 16 km.

Substituting these values into the formula gives:

B = 0.2 / (0.15 * 10^-6 s/km * 16 km) = 0.2 / (2.4 * 10^-6 s) = 83.33 * 10^6 Hz = 83.33 MHz

However, none of the options provided (3.3 MHz, 4.2 MHz, 4.6 MHz, 3.9 MHz) match this result. There may be a mistake in the question or the provided options.

Question

The maximum possible bandwidth (B) of a fiber optic cable can be estimated using the following formula:

B = 0.2 / (tp * L)

where:
- tp is the total pulse broadening, and
- L is the distance.

In this case, tp = 0.15 μs and L = 16 km.

Substituting these values into the formula gives:

B = 0.2 / (0.15 * 10^-6 s/km * 16 km) = 0.2 / (2.4 * 10^-6 s) = 83.33 * 10^6 Hz = 83.33 MHz

However, none of the options provided (3.3 MHz, 4.2 MHz, 4.6 MHz, 3.9 MHz) match this result. There may be a mistake in the question or the provided options.

Knowee AI · Accepted Answer

The maximum possible bandwidth (B) of a fiber optic cable can be estimated using the following formula:

B = 0.2 / (tp * L)

where:
- tp is the total pulse broadening, and
- L is the distance.

In this case, tp = 0.15 μs and L = 16 km.

Substituting these values into the formula gives:

B = 0.2 / (0.15 * 10^-6 s/km * 16 km) = 0.2 / (2.4 * 10^-6 s) = 83.33 * 10^6 Hz = 83.33 MHz

However, none of the options provided (3.3 MHz, 4.2 MHz, 4.6 MHz, 3.9 MHz) match this result. There may be a mistake in the question or the provided options.

A multimode graded index fiber exhibits a total pulse broadening of 0.15μsover a distance of 16 km. Estimate the maximum possible bandwidth, assuming no intersymbol interference.a.3.3 MHzb.4.2 MHzc.4.6 MHzd.3.9 MHz

Question

Solution

Similar Questions

Upgrade your grade with Knowee