Factorize :i. 3x2y+9xy2–15xy ii. 2222 cb4916ba361 iii. 16x2–24yz–9y2–16z2 iv. (x–2y)2–6(x–2y)+5

Sure, let's factorize each expression one by one:

i. 3x²y + 9xy² - 15xy First, we can factor out the common factor, which is 3xy: 3xy(x + 3y - 5)

ii. 2222cb - 4916ba - 361 This expression doesn't seem to be factorizable as it is. It might be a typo or it needs more context to be factorized.

iii. 16x² - 24yz - 9y² - 16z² This is a quadratic equation in two variables. We can rearrange it and factorize: 16x² - 16z² - 24yz + 9y² = 16(x² - z²) - y²(3z - 3)² = 4(x - z)(4x + 4z) - (3y - 3z)(3y + 3z)

iv. (x–2y)² – 6(x–2y) + 5 This is a quadratic equation in the form of (a-b)² - 2ab + b². We can factorize it as: = [(x - 2y) - √5][(x - 2y) + √5]