0.0 atm, given that its density at thesurface is 1.03 × 103 kg-m–3, the compressibility ofwater is 45.8 × 10–11 Pa–1.(a) 1.034 × 102 kg-m–3 (b) 1.034 × 106 kg-m–3(c) 1.034 × 103 kg-m–3 (d) 2.42 × 105 kg-m–3105. Compute the bulk modulus of water from thefollowing data.Initial volume = 100 L, pressure increase = 100 atm(1 atm= 1.013 × 105 Pa),Final volume = 100.5 L. The ratio of the bulk modulusof water with that of air is(a) 4 × 109 (b) 2026 × 104(c) 2.026 × 109 (d) 1 × 105106. Four identical hollow cylindrical columns of mild steelsupport a big structure of mass 50000 kg. The innerand outer radii of each column are 30 cm and 60 cm,respectively. Assuming the load distribution to beuniform, calculate the compressional strain of eachcolumn. Young's modulus, Y = 2.0 × 1011 Pa.(a) 4 × 10–6 (b) 9 × 10–3(c) 8.2 × 10–4 (d) 7.22 × 10–7107. Two strips of metal are riveted together at their endsby four rivets, each of diameter 6 mm. What is themaximum tension that can be exerted by the rivetedstrip, if the shearing stress on the rivet is not to exceed6.9 × 107 Pa? Assume that each rivet is to carryone-quarter of the load.(a) 9 × 102 N (b) 1.23 × 102 N(c) 7.8 × 103 N (d) 8 × 102 N108. How much should the pressure on a litre of water bechanged to compress it by 0.10%. Bulk modulus ofelasticity of water is 2.2 × 10 Nm .(a) 2.4 × 103 Nm2 (b) 2.2 × 106 Nm2(c) 4 × 104 Nm2 (d) 6 × 105 Nm2109. What is the volume of contraction of a solid coppercube, 10 cm on an edge, when subjected to a hydraulicpressure of 7 × 106 Pa? K for copper = 140×109 Pa.(a) 5 × 10–6 m3 (b) 5 × 10–8 m3(c) 9 × 10–4 m3 (d) 3 × 10–6 m3110. A steel cable with a radius of 1.5 cm supports a chairlift. If the maximum stress is not to exceed 108Nm–2, what is maximum load that cable can support?(a) 9 × 103 N (b) 7 × 103 N(c) 7.1 × 104 N (d) 4 × 106 NNCERT EXEMPLAR111. Modulus of rigidity of ideal liquid is(a) infinity

To answer the given questions step by step:

(a) To find the compressibility of water, we are given the density at the surface, which is 1.03 × 10^3 kg/m^3. The compressibility of water is given as 45.8 × 10^(-11) Pa^(-1). Therefore, the answer is (c) 1.034 × 10^3 kg/m^3.

(b) To compute the bulk modulus of water, we are given the initial volume (100 L), pressure increase (100 atm), and final volume (100.5 L). We know that 1 atm is equal to 1.013 × 10^5 Pa. Using the formula for bulk modulus, we can calculate the bulk modulus of water. The ratio of the bulk modulus of water with that of air is (c) 2.026 × 10^9.

(c) To calculate the compressional strain of each column, we are given the mass of the structure (50000 kg) and the inner and outer radii of each column (30 cm and 60 cm). We also know the Young's modulus of mild steel, which is 2.0 × 10^11 Pa. Using the formula for compressional strain, we can calculate the compressional strain of each column. The answer is (c) 8.2 × 10^(-4).

(d) To find the maximum tension that can be exerted by the riveted strip, we are given the diameter of each rivet (6 mm) and the maximum shearing stress on the rivet (6.9 × 10^7 Pa). We assume that each rivet carries one-quarter of the load. Using the formula for maximum tension, we can calculate the maximum tension. The answer is (c) 7.8 × 10^3 N.

(a) To calculate the pressure change required to compress a liter of water by 0.10%, we are given the bulk modulus of elasticity of water (2.2 × 10^9 N/m^2). Using the formula for pressure change, we can calculate the required pressure change. The answer is (c) 4 × 10^4 N/m^2.

(d) To find the volume of contraction of a solid copper cube, we are given the edge length of the cube (10 cm) and the hydraulic pressure applied (7 × 10^6 Pa). We also know the bulk modulus of copper, which is 140 × 10^9 Pa. Using the formula for volume change, we can calculate the volume of contraction. The answer is (d) 3 × 10^(-6) m^3.

(b) To determine the maximum load that a steel cable with a radius of 1.5 cm can support, we are given the maximum stress (10^8 N/m^2). Using the formula for maximum load, we can calculate the maximum load. The answer is (b) 7 × 10^3 N.

(a) The modulus of rigidity of an ideal liquid is infinity.