The distribution of lengths of salmon from a certain river is approximately normal with standard deviation 3.5 inches. If 10 percent of salmon are longer than 30 inches, which of the following is closest to the mean of the distribution? 26 inches 28 inches 30 inches 33 inches E 34 inches
Question
The distribution of lengths of salmon from a certain river is approximately normal with standard deviation 3.5 inches. If 10 percent of salmon are longer than 30 inches, which of the following is closest to the mean of the distribution? 26 inches 28 inches 30 inches 33 inches E 34 inches
Solution
To solve this problem, we need to use the concept of z-scores in a normal distribution. A z-score tells us how many standard deviations an element is from the mean.
The z-score for the 90th percentile (since 10 percent of salmon are longer than 30 inches, 90 percent are shorter) is approximately 1.28 (you can find this value in a standard z-score table or use a calculator that provides this value).
We can set up the following equation to solve for the mean (μ):
30 = μ + 1.28(3.5)
Solving for μ gives us:
μ = 30 - 1.28(3.5) μ = 30 - 4.48 μ = 25.52
So, the mean of the distribution is closest to 26 inches.
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