Calculate (2 + 3i)(−1 + 4i) and represent the answer in exponential form.
Question
Calculate (2 + 3i)(−1 + 4i) and represent the answer in exponential form.
Solution
Sure! To calculate (2 + 3i)(−1 + 4i), we can use the distributive property of multiplication.
Step 1: Multiply the real parts: 2 * -1 = -2
Step 2: Multiply the imaginary parts: 3i * -1 = -3i
Step 3: Multiply the real part of the first number with the imaginary part of the second number: 2 * 4i = 8i
Step 4: Multiply the imaginary part of the first number with the imaginary part of the second number: 3i * 4i = 12i^2
Step 5: Simplify the result: 12i^2 = 12 * -1 = -12
Step 6: Combine the real and imaginary parts: -2 + (-3i) + 8i - 12 = -14 + 5i
So, (2 + 3i)(−1 + 4i) equals -14 + 5i.
To represent the answer in exponential form, we can use Euler's formula, which states that e^(ix) = cos(x) + isin(x).
In this case, the real part is -14 and the imaginary part is 5. So, the exponential form of the answer is:
e^(-14 + 5i) = e^(-14) * e^(5i)
Therefore, the answer in exponential form is e^(-14) * e^(5i).
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