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If L is a finite lattice then L is*boundedinfimumunboundedsupremum

Question

If L is a finite lattice then L is*boundedinfimumunboundedsupremum

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Solution

It seems like your question got cut off or wasn't fully formed. However, I can tell you that a finite lattice L is both bounded and has a supremum and infimum.

Here's why:

  1. Bounded: A lattice L is said to be bounded if it has a greatest element (also known as the supremum or top) and a least element (also known as the infimum or bottom). In a finite lattice, you can always find a greatest and least element by comparing all elements, so it is bounded.

  2. Supremum: The supremum (or least upper bound) of a subset S of a lattice L is an element of L that is greater than or equal to every element of S, and is less than or equal to any upper bound of S. In a finite lattice, you can always find such an element by comparing all elements of S and their upper bounds, so a supremum exists.

  3. Infimum: The infimum (or greatest lower bound) of a subset S of a lattice L is an element of L that is less than or equal to every element of S, and is greater than or equal to any lower bound of S. In a finite lattice, you can always find such an element by comparing all elements of S and their lower bounds, so an infimum exists.

So, a finite lattice is bounded and has both a supremum and infimum.

This problem has been solved

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