To solve this problem, we can use the mirror formula which is 1/f = 1/v + 1/u. Here, f is the focal length of the mirror, v is the image distance, and u is the object distance.

Given in the problem, the focal length f = -12 cm (it's negative because rear view mirrors are convex mirrors and for convex mirrors, the focal length is taken as negative) and the object distance u = -6 cm (it's negative because the object is placed in front of the mirror).

Substituting these values into the mirror formula, we get:

1/-12 = 1/v + 1/-6
1/-12 - 1/-6 = 1/v
-1/12 + 1/6 = 1/v
1/v = 1/12
v = -12 cm

The negative sign indicates that the image is formed on the same side as the object.

As for the nature of the image, in a convex mirror, the image is always virtual (because it's formed on the same side as the object), erect (upright), and diminished (smaller than the object).

So, the image of the object will appear at -12 cm and the nature of the image will be virtual, erect, and diminished.

Question

To solve this problem, we can use the mirror formula which is 1/f = 1/v + 1/u. Here, f is the focal length of the mirror, v is the image distance, and u is the object distance.

Given in the problem, the focal length f = -12 cm (it's negative because rear view mirrors are convex mirrors and for convex mirrors, the focal length is taken as negative) and the object distance u = -6 cm (it's negative because the object is placed in front of the mirror).

Substituting these values into the mirror formula, we get:

1/-12 = 1/v + 1/-6
1/-12 - 1/-6 = 1/v
-1/12 + 1/6 = 1/v
1/v = 1/12
v = -12 cm

The negative sign indicates that the image is formed on the same side as the object.

As for the nature of the image, in a convex mirror, the image is always virtual (because it's formed on the same side as the object), erect (upright), and diminished (smaller than the object).

So, the image of the object will appear at -12 cm and the nature of the image will be virtual, erect, and diminished.

Knowee AI · Accepted Answer

To solve this problem, we can use the mirror formula which is 1/f = 1/v + 1/u. Here, f is the focal length of the mirror, v is the image distance, and u is the object distance.

Given in the problem, the focal length f = -12 cm (it's negative because rear view mirrors are convex mirrors and for convex mirrors, the focal length is taken as negative) and the object distance u = -6 cm (it's negative because the object is placed in front of the mirror).

Substituting these values into the mirror formula, we get:

1/-12 = 1/v + 1/-6
1/-12 - 1/-6 = 1/v
-1/12 + 1/6 = 1/v
1/v = 1/12
v = -12 cm

The negative sign indicates that the image is formed on the same side as the object.

As for the nature of the image, in a convex mirror, the image is always virtual (because it's formed on the same side as the object), erect (upright), and diminished (smaller than the object).

So, the image of the object will appear at -12 cm and the nature of the image will be virtual, erect, and diminished.

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