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How much should Michelle have in a savings account that is earning 3.50% compounded quarterly, if he plans to withdraw $1,500 from this account at the end of every quarter for 5 years? Round to the nearest cent

Question

How much should Michelle have in a savings account that is earning 3.50% compounded quarterly, if he plans to withdraw $1,500 from this account at the end of every quarter for 5 years? Round to the nearest cent

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Solution

To determine how much Michelle should have in a savings account that earns 3.50% interest compounded quarterly, and from which she plans to withdraw $1,500 at the end of every quarter for 5 years, we need to use the formula for the present value of an annuity. The formula is:

PV=PMT×(1(1+r)n)/r PV = PMT \times \left(1 - (1 + r)^{-n}\right) / r

Where:

  • PV PV is the present value (the amount Michelle needs to have in the account initially).
  • PMT PMT is the payment amount per period ($1,500).
  • r r is the interest rate per period.
  • n n is the total number of periods.

First, we need to determine the values for r r and n n :

  1. The annual interest rate is 3.50%, so the quarterly interest rate r r is: r=3.50%4=0.0354=0.00875 r = \frac{3.50\%}{4} = \frac{0.035}{4} = 0.00875

  2. The total number of periods n n is: n=5 years×4 quarters/year=20 quarters n = 5 \text{ years} \times 4 \text{ quarters/year} = 20 \text{ quarters}

Now, we can plug these values into the formula:

PV=1500×(1(1+0.00875)20)/0.00875 PV = 1500 \times \left(1 - (1 + 0.00875)^{-20}\right) / 0.00875

First, calculate (1+0.00875)20 (1 + 0.00875)^{-20} :

(1+0.00875)200.8356 (1 + 0.00875)^{-20} \approx 0.8356

Next, calculate 10.8356 1 - 0.8356 :

10.8356=0.1644 1 - 0.8356 = 0.1644

Now, divide by the quarterly interest rate r r :

0.16440.0087518.7943 \frac{0.1644}{0.00875} \approx 18.7943

Finally, multiply by the payment amount PMT PMT :

PV=1500×18.794328191.45 PV = 1500 \times 18.7943 \approx 28191.45

Therefore, Michelle should have approximately $28,191.45 in the savings account.

This problem has been solved

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