class Sample{     private double num = 100;   private int square(int a){ return a*a;   }}  public class Test{   public static void main(String args[]){   Sample obj = new Sample();   System.out.println(obj.num);  System.out.println(obj.square(10));   }  }Select one:a.Compile time errorb.100c.Run time errord.Executes but no output

What is the output of the above program?class Num { Num(double x ){ System.out.println( x ) ; } }public class Test extends Num { public static void main(String[] args){ Num num = new Num( 2 ) ; } }02.0Compile time error None of the above

What is the Output of following Java Program?abstract class Demo{    public int a;    Demo()    {        a = 10;    }     abstract public void set(); }class Test extends Demo{     final public void get()    {        System.out.println("a = " + a);    }     public static void main(String[] args)    {        Test obj = new Test();        obj.get();    }}Select one:a.Runtime Exceptionb.a=10c.Compile Time Error

Determine the outputpublic class Trial{public static void main(String[] args)                {                                int arr[4]={};                                System.out.print(arr[0]);                }}Select one:a.Garbage errorb.Compile time errorc.Runtime errord.0

Consider the below code snippet  and determine the output.class Student{ private int studentId; private float average;}class Test{ public static void main(String a[]) { Student s=new Student(); s.studentId=123; System.out.println(s.studentId); }}Select one:a.Compile time errorb.1c.0d.Any value

Analyze the following code: public class Test { public static void main(String[] args) { int n = 2; square(n); } void square(int n) { System.out.print(n + " square is " + n * n); }}The program has a compile error because method square(int n) does not return a value.The program has a compile error because method square(int n) is not declared static.The program runs fine.The program prints2 square is 4