To answer this question, we need to look at the electron configuration of each atom.

1. Mg (Magnesium) - [Ne] 3s². All electrons are paired.
2. S (Sulfur) - [Ne] 3s² 3p⁴. There are two unpaired electrons in the 3p orbital.
3. Ga (Gallium) - [Ar] 3d¹⁰ 4s² 4p¹. There is one unpaired electron in the 4p orbital.
4. He (Helium) - 1s². All electrons are paired.
5. V (Vanadium) - [Ar] 3d³ 4s². There is one unpaired electron in the 3d orbital.

So, the atom with exactly two unpaired electrons in the ground electronic state is Sulfur (S).

Question

To answer this question, we need to look at the electron configuration of each atom.

1. Mg (Magnesium) - [Ne] 3s². All electrons are paired.
2. S (Sulfur) - [Ne] 3s² 3p⁴. There are two unpaired electrons in the 3p orbital.
3. Ga (Gallium) - [Ar] 3d¹⁰ 4s² 4p¹. There is one unpaired electron in the 4p orbital.
4. He (Helium) - 1s². All electrons are paired.
5. V (Vanadium) - [Ar] 3d³ 4s². There is one unpaired electron in the 3d orbital.

So, the atom with exactly two unpaired electrons in the ground electronic state is Sulfur (S).

Knowee AI · Accepted Answer

To answer this question, we need to look at the electron configuration of each atom.

1. Mg (Magnesium) - [Ne] 3s². All electrons are paired.
2. S (Sulfur) - [Ne] 3s² 3p⁴. There are two unpaired electrons in the 3p orbital.
3. Ga (Gallium) - [Ar] 3d¹⁰ 4s² 4p¹. There is one unpaired electron in the 4p orbital.
4. He (Helium) - 1s². All electrons are paired.
5. V (Vanadium) - [Ar] 3d³ 4s². There is one unpaired electron in the 3d orbital.

So, the atom with exactly two unpaired electrons in the ground electronic state is Sulfur (S).

Which of the following atoms has exactly two unpaired electrons in the ground electronic state? Mg S Ga He V

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