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The sum of a number and 18 is divided by −2 to give 3.−2 times three less than a number is equal to 18.A number is divided by 3, then −2 is subtracted to give 18.A number is multiplied by −2, then 3 is subtracted to give 18.−2𝑥−3=18−2×(𝑥−3)=18 𝑥3+2=18 𝑥+18−2=3

Question

The sum of a number and 18 is divided by −2 to give 3.−2 times three less than a number is equal to 18.A number is divided by 3, then −2 is subtracted to give 18.A number is multiplied by −2, then 3 is subtracted to give 18.−2𝑥−3=18−2×(𝑥−3)=18 𝑥3+2=18 𝑥+18−2=3

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Solution

It seems like you have multiple equations here. Let's solve them one by one:

  1. The sum of a number and 18 is divided by -2 to give 3. Let's denote the number as x. The equation becomes: (x + 18) / -2 = 3 Multiply both sides by -2 to get rid of the division: x + 18 = -6 Subtract 18 from both sides to solve for x: x = -6 - 18 = -24

  2. -2 times three less than a number is equal to 18. The equation becomes: -2 * (x - 3) = 18 Divide both sides by -2: x - 3 = -9 Add 3 to both sides to solve for x: x = -9 + 3 = -6

  3. A number is divided by 3, then -2 is subtracted to give 18. The equation becomes: x / 3 - 2 = 18 Add 2 to both sides: x / 3 = 20 Multiply both sides by 3 to solve for x: x = 20 * 3 = 60

  4. A number is multiplied by -2, then 3 is subtracted to give 18. The equation becomes: -2x - 3 = 18 Add 3 to both sides: -2x = 21 Divide both sides by -2 to solve for x: x = 21 / -2 = -10.5

So, the solutions for x in each of the equations are -24, -6, 60, and -10.5 respectively.

This problem has been solved

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