It takes 11.2 kJ of energy to raise the temperature of 145 g of benzene from 25.0°C to 70.0°C. What is the specific heat of benzene? Group of answer choices1.7 J/g°C3.6 J/g°C4.1 J/g°C1.0 J/g°C
Question
It takes 11.2 kJ of energy to raise the temperature of 145 g of benzene from 25.0°C to 70.0°C. What is the specific heat of benzene? Group of answer choices1.7 J/g°C3.6 J/g°C4.1 J/g°C1.0 J/g°C
Solution
The specific heat of a substance can be calculated using the formula:
q = mcΔT
where: q = heat energy absorbed or released (in joules or J) m = mass of the substance (in grams or g) c = specific heat capacity (in J/g°C) ΔT = change in temperature (in °C)
Given: q = 11.2 kJ = 11200 J (since 1 kJ = 1000 J) m = 145 g ΔT = 70.0°C - 25.0°C = 45.0°C
We need to find c.
Rearranging the formula to solve for c gives:
c = q / (mΔT)
Substituting the given values gives:
c = 11200 J / (145 g * 45.0°C) = 1.7 J/g°C
So, the specific heat of benzene is 1.7 J/g°C.
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