To solve this problem, we first need to understand the total number of outcomes when a fair coin is tossed twice. A fair coin has 2 outcomes (Head or Tail), so when tossed twice, we have 2*2 = 4 outcomes in total. These outcomes are HH, HT, TH, TT.

The event of getting at least one head includes the outcomes HH, HT, TH. So there are 3 favorable outcomes.

The probability of an event is given by the ratio of the number of favorable outcomes to the total number of outcomes.

So, the probability of getting at least one head when a fair coin is tossed twice is 3/4.

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To solve this problem, we first need to understand the total number of outcomes when a fair coin is tossed twice. A fair coin has 2 outcomes (Head or Tail), so when tossed twice, we have 2*2 = 4 outcomes in total. These outcomes are HH, HT, TH, TT.

The event of getting at least one head includes the outcomes HH, HT, TH. So there are 3 favorable outcomes.

The probability of an event is given by the ratio of the number of favorable outcomes to the total number of outcomes.

So, the probability of getting at least one head when a fair coin is tossed twice is 3/4.

Knowee AI · Accepted Answer

To solve this problem, we first need to understand the total number of outcomes when a fair coin is tossed twice. A fair coin has 2 outcomes (Head or Tail), so when tossed twice, we have 2*2 = 4 outcomes in total. These outcomes are HH, HT, TH, TT.

The event of getting at least one head includes the outcomes HH, HT, TH. So there are 3 favorable outcomes.

The probability of an event is given by the ratio of the number of favorable outcomes to the total number of outcomes.

So, the probability of getting at least one head when a fair coin is tossed twice is 3/4.

A fair coin is tossed twice, what is the probability of getting at least one head?*1/41/31/23/4

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