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Can we conclude, using a .05 level of significance,that the miles-per-gallon (mpg) performance of Model Ais greater than the miles-per-gallon performance of Model B?  Model AModel BSample Size2428Sample Mean29.827.3Sample standard deviation2.561.81 What is the conclusion?Group of answer choicesDo not Reject HoRevise HoReject HoNo answer text provided.

Question

Can we conclude, using a .05 level of significance,that the miles-per-gallon (mpg) performance of Model Ais greater than the miles-per-gallon performance of Model B?  Model AModel BSample Size2428Sample Mean29.827.3Sample standard deviation2.561.81 What is the conclusion?Group of answer choicesDo not Reject HoRevise HoReject HoNo answer text provided.

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Solution

To answer this question, we need to conduct a hypothesis test for the difference between two means. Here are the steps:

  1. State the null hypothesis (Ho) and the alternative hypothesis (Ha). In this case, the null hypothesis is that the mean mpg of Model A is less than or equal to the mean mpg of Model B (Ho: μA ≤ μB). The alternative hypothesis is that the mean mpg of Model A is greater than the mean mpg of Model B (Ha: μA > μB).

  2. Calculate the test statistic. This is done using the formula for the test statistic for the difference between two means.

  3. Determine the critical value for a .05 level of significance. Since this is a one-tailed test (we're only interested in whether Model A has a greater mpg), the critical value for a .05 level of significance is 1.645 (or -1.645 for a lower-tailed test).

  4. Compare the test statistic to the critical value. If the test statistic is greater than the critical value, we reject the null hypothesis.

  5. Make the decision. If we reject the null hypothesis, we conclude that the mean mpg of Model A is greater than the mean mpg of Model B. If we do not reject the null hypothesis, we do not have enough evidence to conclude that the mean mpg of Model A is greater than the mean mpg of Model B.

Without the actual calculations, I can't provide a definitive answer. However, these are the steps you would follow to reach a conclusion.

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Similar Questions

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A local car manufacturer manufactures small automobiles that averaged 50 miles per gallon of gasoline in highway driving.The company has developed a more efficient engine for its small cars and now advertises that its new small cars average more than 50 miles per gallon in highway driving.  In a sample of 36 road-tested automobiles,  it showed an average of 51.5 miles per gallon and a standard deviation of 6 miles per gallon.Test to determine whether or not the manufacturer's advertising campaign is legitimate at 0.05 level of significance and using the p-value approach,  Group of answer choicesWith p-value of 0.0668, therefore, do not reject Ho. There is no sufficient evidence to conclude that the new cars average more than 50 mile per gallon.With p-value of 0.0068, therefore, reject Ho. There is sufficient evidence to conclude that the new cars average more than 50 miles per gallon.With p-value of 0.0724, therefore, do not reject Ho. There is no sufficient to conclude that the new cars average more than 50 miles per gallon.With p-value of 0.0008, therefore, reject Ho. There is sufficient evidence to conclude that the new cars average more than 50 miles per gallon.

A car manufacturer advertises that its new subcompact models get 47 miles per gallon (mpg). Let µ be the mean of the mileage distribution for these cars. You assume that the manufacturer will not underrate the car, but you suspect that the mileage might be overrated. State the null hypothesis and the alternate hypothesis for this case.a.H0: µ = 47mpg  and H1: µ ≠ 47mpgb.H0: µ = 47mpg  and H1: µ < 47mpgc.H0: µ = 47mpg  and H1: µ > 47mpgd.H0: µ ≥ 47mpg  and H1: µ < 47mpg

Based on the p-value, what is your conclusion (use .05 significance level)?

A consumer claims that car model of type 1 has a lower average miles per gallon than all other cars on the market. Which of the following is the correct null hypothesis?Question 11Answera.µ < µ0b.µ = µ0c.µ ≥ µ0d.µ > µ0

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