The number of states in a sequential circuit is determined by the number of flip-flops it contains. Each flip-flop can be in one of two states, either 0 or 1.

So, for a sequential circuit with 3 D-Flip flops, the number of states is 2^n, where n is the number of flip-flops.

Here, n = 3.

So, the number of states is 2^3 = 8.

Therefore, a sequential circuit with 3 D-Flip flops has 8 states.

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The number of states in a sequential circuit is determined by the number of flip-flops it contains. Each flip-flop can be in one of two states, either 0 or 1.

So, for a sequential circuit with 3 D-Flip flops, the number of states is 2^n, where n is the number of flip-flops.

Here, n = 3.

So, the number of states is 2^3 = 8.

Therefore, a sequential circuit with 3 D-Flip flops has 8 states.

Knowee AI · Accepted Answer

The number of states in a sequential circuit is determined by the number of flip-flops it contains. Each flip-flop can be in one of two states, either 0 or 1.

So, for a sequential circuit with 3 D-Flip flops, the number of states is 2^n, where n is the number of flip-flops.

Here, n = 3.

So, the number of states is 2^3 = 8.

Therefore, a sequential circuit with 3 D-Flip flops has 8 states.

A sequential circuit contains 3 D-Flip flops. How many states are present?Group of answer choices12368

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