What is the output of the following code snippet?class Node: def __init__(self, value): self.data = value self.left = None self.right = Nonedef calculate_sum(node): if node is None: return 0 return node.data + calculate_sum(node.left) + calculate_sum(node.right) # Usage example:root = Node(1)root.left = Node(2)root.right = Node(3)root.left.left = Node(4)root.left.right = Node(5)print(calculate_sum(root))Options115106
Question
What is the output of the following code snippet?class Node: def init(self, value): self.data = value self.left = None self.right = Nonedef calculate_sum(node): if node is None: return 0 return node.data + calculate_sum(node.left) + calculate_sum(node.right) # Usage example:root = Node(1)root.left = Node(2)root.right = Node(3)root.left.left = Node(4)root.left.right = Node(5)print(calculate_sum(root))Options115106
Solution
The output of the given code snippet will be 15.
Here's how:
The calculate_sum function is a recursive function that sums up the data of the given node and the sums of its left and right children. If a node is None (i.e., it doesn't exist), it contributes 0 to the sum.
The tree structure created by the usage example is as follows:
1
/ \
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