Consider the following for loops: A) for(i = 0; i < n; i++) B) for(i = 0; i < n; i += 2) C) for(i = 1; i < n; i *= 2) D) for(i = n; i > -1; i /= 2)Which loop will execute fastest?
Question
Consider the following for loops: A) for(i = 0; i < n; i++) B) for(i = 0; i < n; i += 2) C) for(i = 1; i < n; i *= 2) D) for(i = n; i > -1; i /= 2)Which loop will execute fastest?
Solution
The speed of a loop is determined by the number of iterations it performs.
A) This loop will execute 'n' times.
B) This loop will execute 'n/2' times (assuming n is even), as it increments by 2 each time.
C) This loop will execute 'log(n)' times (base 2), as it doubles the value of 'i' each time.
D) This loop will also execute 'log(n)' times (base 2), as it halves the value of 'i' each time.
Therefore, loops C and D will execute the fastest as they have the least number of iterations (logarithmic complexity), assuming 'n' is a large number.
Similar Questions
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