Two forces P and Q acts on a hook as shown.             Given: P = 100 N; θ1 = 19°If Q = 200 kN, find θ2 such that the resultant of the forces is vertically downward.QUESTION 8ANSWERA.61.79°B.60.79°C.59.97°D.62.68°Clear my choice

The problem involves two forces, P and Q, acting on a hook. The force P is given as 100 N and is acting at an angle of 19°. The force Q is given as 200 kN. We are asked to find the angle θ2 such that the resultant of the forces is vertically downward.

The resultant force (R) of two forces can be found using the formula:

R = sqrt(P^2 + Q^2 + 2PQcosθ)

Since the resultant force is vertically downward, the horizontal components of the forces should cancel each other out. This means that the horizontal component of force P should be equal to the horizontal component of force Q.

The horizontal component of a force can be found using the formula:

Horizontal component = Force * cos(Angle)

Setting the horizontal components of the forces equal to each other gives:

Pcosθ1 = Qcosθ2

Substituting the given values gives:

100cos19° = 200000cosθ2

Solving for θ2 gives:

cosθ2 = (100cos19°) / 200000

θ2 = cos^-1[(100cos19°) / 200000]

Calculating this gives a value for θ2. Compare this value with the options given to find the correct answer.