find the output of given code.#include <stdio.h>int main(){int a,b=110,c=20;printf("%d",a=b-=c*=5);return 0;}

The given code is written in C language. Here's a step-by-step explanation of what the code does:

1. It declares three integer variables a, b, and c with b initialized to 110 and c initialized to 20.

2. The expression c*=5 is equivalent to c = c * 5. So, c becomes 100.

3. The expression b-=c is equivalent to b = b - c. So, b becomes 10 (110 - 100).

4. The expression a=b assigns the value of b to a. So, a becomes 10.

5. The printf function prints the value of a, which is 10.

So, the output of the given code will be 10.